join_with_view용 추론 가이드`std::ranges::join_with_view`

헤더 `<ranges>`
template< class R, class P > join_with_view( R&&, P&& ) -> join_with_view<views::all_t<R>, views::all_t<P>>;	에 정의됨 (1)	(C++23부터)
template< class R > join_with_view( R&&, ranges::range_value_t<ranges::range_reference_t<R>> ) -> join_with_view<views::all_t<R>, ranges::single_view< ranges::range_value_t<ranges::range_reference_t<R>>>;	(2)	(C++23부터)

다음 추론 가이드는 join_with_view에 대해 범위와 구분자로부터의 추론을 허용하기 위해 제공됩니다.

1) 구분자가 요소의 범위입니다.

2) 구분자가 단일 요소입니다.

멤버 함수
join_with_view::join_with_view
join_with_view::base
join_with_view::begin
join_with_view::end
추론 가이드
반복자
멤버 함수
join_with_view::iterator::iterator
join_with_view::iterator::operator*
join_with_view::iterator::operator++ join_with_view::iterator::operator++(int) join_with_view::iterator::operator-- join_with_view::iterator::operator--(int)
비멤버 함수
operator==(join_with_view::iterator) (C++23)
iter_move(join_with_view::iterator) (C++23)
iter_swap(join_with_view::iterator) (C++23)
Sentinel
join_with_view::sentinel::sentinel
operator==(join_with_view::sentinel) (C++23)

join_with_view용 추론 가이드std::ranges::join_with_view